00:01
Starting with our balanced chemical equation, we have potassium acid phthalate.
00:09
It's going to react with sodium hydroxide.
00:11
This would give me k, na, c8, h4, o4, and h2o.
00:20
This question we're told that we've got 0 .728 grams of the potassium acid phthalate, and that requires 32 .2 milliliters of naoh.
00:31
For neutralization, we want to start by finding the moles of the naoh.
00:36
The stoichiometry calculation, so we've got 0 .728 grams of the k, h, c, 8, h, 4, o, 4...