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A block of solid aluminum sits on a flat, level surface. Aluminum has a density of 2.71 × 10^3 kg/m^3. The mass of the block is 23.8 kg. (a) What is the volume of the block (in m^3)? _________ (b) The amount of surface area of the block in contact with the surface is 3.53 × 10^(-2) m^2. What is the average pressure (in Pa) exerted on the surface by the block? _____________ Pa
Added by Sara R.
Step 1
Rearranging the formula to solve for volume gives us volume = mass / density. Plugging in the given values, we get volume = 23.8 kg / (2.71 × 10^3 kg/m^3) = 8.78 × 10^(-3) m^3. Show more…
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