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Question

$\frac{1}{2}H$ $6\cos{4t}$ $1\Omega$ $\frac{1}{4}H$ $\frac{1}{8}F$ $0,4\Omega$ $3\cos{4t}$

          
            $\frac{1}{2}H$
$6\cos{4t}$
$1\Omega$
$\frac{1}{4}H$
$\frac{1}{8}F$
$0,4\Omega$
$3\cos{4t}$

(1)/(2)H
6cos4t
1Ω
(1)/(4)H
(1)/(8)F
0,4Ω
3cos4t

Added by David R.

Instant Answer

Step 1

The power triangle represents the relationship between real power (P), reactive power (Q), and apparent power (S). Given: H = 1/4 H H = 1/2 I I = 6cos(4t) V = 10 P = 0.4 I = 3cos(4t) To find the reactive power value required to achieve a power factor of 0.95 Show more…

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