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Find the fifth root of 32i that graphs in the first quadrant: 2 ](cos[ Jo + i sin[ 19) Use degree measure:
Added by Michael J.
Step 1
32i can be written as 0 + 32i, so its magnitude is 32 and its angle is 90 degrees (since it lies on the positive imaginary axis). Therefore, in polar form, 32i = 32(cos(90°) + i sin(90°)). Show more…
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