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A golf ball is launched with the initial conditions shown in the figure. Determine the radius of curvature of the trajectory and the time rate of change of the speed of the ball ( $a$ ) just after launch and $(b)$ at apex. Neglect aerodynamic drag.
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This can be done by multiplying the given velocity by 0.44704. So, the velocity in meters per second is $165 \times 0.44704 = 73.76 \, \text{m/s}$. Show more…
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