We set the function equal to zero and solve for $x$.
$$f(x)=\left(2 x^{2}+5\right)(x-8)^{2}(x+1)^{3}=0$$
The zeros of the function are the values of $x$ that make each factor equal to zero. The first factor, $2x^2+5$, is always positive for all real $x$, so it
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