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The electrolysis of $\mathrm{MgCl}_{2}(\mathrm{aq})$ can be represented as $\mathrm{Mg}^{2+}(\mathrm{aq})+2 \mathrm{Cl}^{-}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(1) \longrightarrow$ $\mathrm{Mg}^{2+}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g})$ The electrolysis of a 315 mL sample of $0.185 \mathrm{M} \mathrm{MgCl}_{2}$ is continued until $0.652 \mathrm{L} \mathrm{H}_{2}(\mathrm{g})$ at $22^{\circ} \mathrm{C}$ and $752 \mathrm{mmHg}$ has been collected. Will $\mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{s})$ precipitate when electrolysis is carried to this point? [Hint: Notice that $\left[\mathrm{Mg}^{2+}\right]$ remains constant throughout the electrolysis, but $\left.\left[\mathrm{OH}^{-}\right] \text {increases. }\right]$

   The electrolysis of $\mathrm{MgCl}_{2}(\mathrm{aq})$ can be represented as $\mathrm{Mg}^{2+}(\mathrm{aq})+2 \mathrm{Cl}^{-}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(1) \longrightarrow$ $\mathrm{Mg}^{2+}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})+\mathrm{H}_{2}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g})$
The electrolysis of a 315 mL sample of $0.185 \mathrm{M} \mathrm{MgCl}_{2}$ is continued until $0.652 \mathrm{L} \mathrm{H}_{2}(\mathrm{g})$ at $22^{\circ} \mathrm{C}$ and $752 \mathrm{mmHg}$ has been collected. Will $\mathrm{Mg}(\mathrm{OH})_{2}(\mathrm{s})$ precipitate when electrolysis is carried to this point? [Hint: Notice that $\left[\mathrm{Mg}^{2+}\right]$ remains constant throughout the electrolysis, but $\left.\left[\mathrm{OH}^{-}\right] \text {increases. }\right]$

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General Chemistry: Principles and Modern Applications

General Chemistry: Principles and Modern Applications

Ralph H. Petrucci,… 10th Edition

Chapter 18, Problem 32

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Step 1

Here, $P$ is the pressure, $V$ is the volume, $n$ is the number of moles, $R$ is the gas constant, and $T$ is the temperature. Substituting the given values, we have: \[P = \frac{752}{760} \, \text{atm}, \, V = 0.652 \, \text{L}, \, R = 0.0821 \, \text{atm L Show more…

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