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Question
The peripheral speed of the tooth of a 10 -in-diameter circular saw blade is $150 \mathrm{ft} / \mathrm{s}$ when the power to the saw is turned off. The speed of the tooth decreases at a constant rate, and the blade comes to rest in $9 \mathrm{s}$. Determine the time at which the total acceleration of the tooth is $130 \mathrm{ft} / \mathrm{s}^{2}$.Show more…
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Step 1
We know that the initial speed of the blade is $150 \mathrm{ft} / \mathrm{s}$ and it comes to rest in $9 \mathrm{s}$. We can use the formula for acceleration (or in this case deceleration) which is change in velocity divided by time. So, the deceleration $a$ is Show more…
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