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Two 100.0-W speakers, A and B, are separated by a distance $D=3.6 \mathrm{~m} .$ The speakers emit in-phase sound waves at a frequency $f=10,000.0 \mathrm{~Hz}$. Point $P_{1}$ is located at $x_{1}=4.50 \mathrm{~m}$ and $y_{1}=0 \mathrm{~m} ;$ point $P_{2}$ is located at $x_{2}=4.50 \mathrm{~m}$Show more…
and $y_{2}=-\Delta y .$ Neglecting speaker $\mathrm{B}$, what is the intensity, $I_{\mathrm{A} 1}$ (in $\mathrm{W} / \mathrm{m}^{2}$ ), of the sound at point $P_{1}$ due to speaker $\mathrm{A}$ ? Assume that the sound from the speaker is emitted uniformly in all directions. What is this intensity in terms of decibels (sound level, $\beta_{\mathrm{A} 1}$ )? When both speakers are turned on, there is a maximum in their combined intensities at $P_{1} .$ As one moves toward $P_{2},$ this intensity reaches a single minimum and then becomes maximized again at $P_{2}$. How far is $P_{2}$ from $P_{1},$ that is, what is $\Delta y ?$ You may assume that $L \gg \Delta y$ and that $D \gg \Delta y$, which will allow you to simplify the algebra by using $\sqrt{a \pm b} \approx a^{1 / 2} \pm \frac{b}{2 a^{1 / 2}}$ when $a \gg b$.
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6 \, \text{m}$, the frequency of the sound $f = 10,000 \, \text{Hz}$, and the distance from speaker A to point $P_1$, $x = 4.5 \, \text{m}$. We are asked to find the distance $\Delta y$ from point $P_1$ to point $P_2$. Show more…
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