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Water flows through a horizontal, $180^{\circ}$ pipe bend as is illustrated in Fig. P5.39. The flow cross-sectional area is constant at a value of $9000 \mathrm{mm}^{2}$. The flow velocity everywhere in the bend is $15 \mathrm{m} / \mathrm{s}$. The pressures at the entrance and exit of the bend are 210 and $165 \mathrm{kPa}$, respectively. Calculate the horizontal ( $x$ and $y$ ) components of the anchoring force needed to hold the bend in place.
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First, we need to find the mass flow rate of the water. We can do this using the formula: mass flow rate = density × area × velocity. The density of water is approximately 1000 kg/m³, and the area is given as 9000 mm², which is equal to 0.009 m². So, the mass flow Show more…
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'5.39 Water flows through horizontal, 1808 pipe bend as is illustrated in Fig: P5.39. The flow cross-sectional area is constant at a value of 9000 mm?_ The flow velocity everywhere in the bend is 15 mls. The pressures at the entrance and exit of the bend are 210 and 165 kPa, respectively Calculate the horizontal (x and y) components of the anchoring force needed to hold the bend in place. Figure P5.39'
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