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What do you expect the products of monochlorination of butane to be? In what ratio will they be formed at $25^{\circ} \mathrm{C}$ ?
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Step 1
First, we need to identify the possible products of monochlorination of butane. Butane (C4H10) can be chlorinated to form two different products: 1-chlorobutane (C4H9Cl) and 2-chlorobutane (C4H9Cl). Show more…
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The balanced equation below shows the products that are formed when butane (C4H10) is combusted. 2C4H10 + 13O2 → 8CO2 + 10H2O What is the mole ratio of butane to carbon dioxide? 2:8 1:5 13:8 13:10
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Take the same alkanes whose percentages of monochlorination products you calculated in Problem $6,$ and calculate what the percentages of monobromination products would be if bromination were carried out at $125^{\circ} \mathrm{C}$.
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